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CGP EDU Academic Team
Published on: September 13, 2026
If there is a positive error of 50% in the measurement of velocity of a body, then the error in the measurement of kinetic energy is
Text Solution
Verified by ExpertsThe correct answer is:
D
Kinetic energy \(\varepsilon - \frac{1}{2} m v^{2}\)
\(\therefore \frac{\Delta E}{E} \times 100 = \frac{v' - v''}{v^2} \times 100\)
\(\left[(1.5)^{2} - 1\right] \times 100\)
\(\frac{\Delta E}{E} \times 100 - 125\%\)
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